We have already discussed Nominal Mix of Concrete and Mix Proportions.

If you have missed that please go ahead and read that. We will wait for you.

It’s time for some calculations.

In this post, we are going to explain “How to Calculate Concrete Volume and its ingredients?”

How to Calculate Concrete Volume?

If it is a volume, then we know there must be 3 dimensions, Length, Height, Width or Breadth.

For Slab, If we need to calculate the concrete volume,

Volume = Length X Breadth X Width/Thickness = 5 X 3 X 0.125 = 3.75 m³

For Beam, If we need to calculate the concrete volume,

Volume = Length X Breadth X Width = 5 X 0.6 X 0.3 = 3.75 m³

For Column, If we need to calculate a concrete volume for the below Columns,

Rectangular Column, Volume = Height X Breadth X Width = 5 X 0.6 X 0.3 = 0.9 m³

Circular Column, Volume = πr² h= 3.141256 X (0.15)² X 5 = 0.35 m³

Concrete Ingredients Calculation

For Cement, Sand and Coarse Aggregate.

This is a Volumetric Calculation.

Assuming we need 2 m³ of concrete for M20 Concrete Mix, (Mix Ratio, M20 = 1 : 1.5 : 3)

Total Part of the Concrete = 1+1.5+3 = 5.5 Parts

Therefore, Cement Quantity = (Cement Part / Concrete Parts ) * Concrete Volume

= (1/5.5)* Concrete Volume = (1/5.5)*2 = 0.3636 m³

Density of Cement = 1440 kg/ m³ = 0.3636 X 1440 = 523 kg = 10.5 Approx. Bags

Sand Quantity = ( Sand Part / Concrete Parts ) * Concrete Volume = (1.5/5.5) * 2 = 0.5454 m³

Coarse Aggregate = (Coarse Aggregate Part / Concrete Parts ) * Concrete Volume

= (3/5.5) * 2 = 1.09 m³

According to IS 10262 (2009), Assuming Water-Cement Ratio for the Concrete as 0.45

Required Amount of Water = W/C Ratio X Cement Volume

Therefore, Water = 0.45 X 0.3636 m³= 0.16362 m³

Unit Weight of Water = 1000 litres/m³

Required Amount of Water = 0.16362 X 1000 = 163.62 litres

Therefore, we need 10.5 bags of cement, 0.5454 m³ of sand, 1.09 m³ of Coarse aggregates and 163.62 litres of water.

Hope you enjoyed the content.

Happy Learning 🙂