# Tile Flooring Cost Estimation

we have learned how to calculate tiles needed for a floor?

Go ahead and read that post in case if you missed it.

In this post, we are going to calculate total tile flooring cost estimation.

For better illustration, we are going to use square metre unit throughout the post.

## Tile flooring process at glance,

- First, we need to fill the flooring area with cement mortar (1:4 ratio) at a minimum thickness (50 mm). we may increase the thickness of the cement sand mortar to adjust the height of the floor.

- Second, we lay the tiles on the cement, sand mortar.

Assume we are going to estimate the cost of tile laying for the below room (Figure.)

**FIGURE **

### Tile Calculation

From the figure,

Size of the room = 4 m × 3 m

Size of the tile = 0.3 m × 0.3 m

Using the formula, from the previous post, number of tiles calculation

we have found that totally 133 number of tiles required for this room. (we have excluded the skirting tiles area)

### Mortar calculation for tile flooring

From the Figure,

Wet Volume of the cement mortar required = Area of the room × Cement Mortar Thickness

= 12 m^{2 }× 0.05 m

**Wet Volume of the cement mortar required = 0.6 m**^{3}

We need 1.5 m^{3}^{ }volume of wet cement mortar that means, we need this much volume after adding water to cement and sand mix.

Dry volume of mortar is considered as 25% of more of wet volume.

Related: Cement Mortar Calculation for Plastering

In order to calculate the dry volume,

Dry Volume of cement mortar = 0.6 m^{3 }X (1+0.25)

= 0.6 m^{3 }X 1.25

** Dry Volume of cement mortar = 0.75 m**^{3}

### Cement and Sand Calculation

Calculate cement and sand for tile flooring, (1:4 ratio)

1 Cement : 4 Sand = Dry Volume of Cement Mortar

1 part of cement : 4 part of sand = 0.75 m3 (Total 5 parts)

So, Cement = 0.75 m^{3} /5

= 0.15 m^{3}

We know 1 bag of cement = 0.035 m^{3}

Required Cement Bags = 0.15 / 0.035

= 4.29 Bags

** Required Cement Bags = 4.3 Bags (Approx)**

So, Required Sand = (0.75 m^{3 }/ 5) X 4

** Required Sand = 0.6 m**^{3}

Therefore,

We need 4.3 Cement Bags, 0.6 m^{3 }Sand and 133 number of tiles required for the room shown in Figure

### Tile Flooring Cost Estimation Example,

Materials | Quantity | Rate (currency) | Cost |
---|---|---|---|

Tile | 133 | 55 / sq.ft | 7315 |

Cement | 4.3 | 350 / bag | 1505 |

Sand | 0.6 | 1450 / m3 | 870 |

Total Amount | 9690 |

You can make use of the below tile flooring cost estimation calculator

If you found this estimation helpful, share it with your friends.

Happy Learning 🙂