In this post, we are going to explain how to calculate steel quantity for the slab? For both one way and two way slab with an example.
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We hope you have already familiar with
If you missed that please read that posts.
Quick Recap,
One Way Slab  Ly/Lx > 2 

Two Way Slab  Ly/Lx < 2 
Slab Reinforcement Calculation
https://www.youtube.com/watch?v=FzIO8jEH67k
One way slab Reinforcement Detailing
The Biggest misconception is considering beam outer to outer as slab span. Please refer the below diagram
Let’s take an example of the below one way slab diagram
Given
 Main bars are 12 mm in diameter @ 150 mm centre to centre spacing
 Distribution bars are 8 mm in diameter @ 150 mm centre to centre spacing. (Main Bar & Distribution Bar Difference)
 Top and Bottom Clear Cover is 25 mm
 Consider Development length as 40 d
 Thickness of Slab – 150 mm
One Way Slab Bar Bending Schedule Calculation
Step 1
FIrst, find number of rods required for main reinforcement and distribution
Number of Bars Formula = (Length of slab / spacing) + 1
Number of Main Bars = (Ly / spacing) + 1 = (5000/150) + 1 = 34 nos
Number of Distribution Bars = (Lx / spacing) + 1 = (2000 / 150) + 1 = 14 nos
Step 2
Find cutting length of main bars and distribution bars
Cutting Length of Main Bar,
= Clear Span of Slab (Lx) + (2 X Developement Length) +(1 x Inclined length) – (45° bend x 2)
Crank Length = 0.42 D, We have already discussed this on Cutting Length of Main Bar post
= 2000 + (2 x 40 x 12) + (1 x 0.42 x D) – (1d x 2)
= 2000 + 960 + 0.42D – (1x12x2) = 2960 +0.42D – 24
D = Slab thickness – 2 side clear cover – dia of bar = 150 – 50 12 = 88 mm
Length of Main Bar = 2960+(0.42 x 88) – 24 = 2973 mm or 2.97 m
Step 3
Find length of distribution bar
= Clear Span (Ly) + (2 x Development Length (Ld))
= 5000 + (2 x 40 x 8) = 5640 mm or 5.64 m
Step 4
Find Top Bar (Extra) ; Top Bars are provided at the top of critical length (L/4) area, Please refer the drawing section AA
Number of top bars = (Lx/4) / spacing + 1 = (2000/4) / 150 +1 = 4 Nos x 2 sides = 8 Nos
Length of Top Bar (L) = same as distribution bars = 5.64 m
Bar Bending Schedule for One Way Slab
Please refer the Bar Bending Shape Code & Steel Weight Calculation post
Two way slab Reinforcement Detailing
Now Calculate Bar Bending Schedule for Two Way Slab.
Let’s take an example the below twoway slab diagram
 Main bars are 12 mm in diameter @ 150 mm centre to centre spacing
 Distribution bars are 8 mm in diameter @ 150 mm centre to centre spacing.
 Top and Bottom Clear Cover is 25 mm
 Development length – 40 d
 Thickness of Slab – 150 mm
One Way Slab Bar Bending Schedule Calculation
Step 1
FIrst, find number of rods required for main reinforcement and distribution
Number of Required Bars Formula = (Length of slab / spacing) + 1
Number of Main Bars = Ly / spacing + 1 = (4000/150) + 1 = 27 nos
Number of Distribution Bars = Lx / spacing + 1 = 3000/150 + 1 = 21 nos
Step 2
Find cutting length of main bars and distribution bars
Cutting Length of Main Bar,
= Clear Span of Slab (Ly) + (1 X Developement Length) +(1 x inclined length) – (45° bend x 2)
Inclined Length = 0.42 D
= 3000 + (1 x 40 x 12) + (1 x 0.42 x D) – (1d x 2)
= 3000 + 480 + 0.42D – (1x12x2) = 3480 + 0.42 D 24
D = Slab thickness – 2 side clear cover – dia of bar = 150 – 50 12 = 88 mm
Length of Main Bar = 3480+(0.42 x 88)24 = 3492.9 mm or 3.49 m
Step 3
Find cutting length of distribution bar
= Clear Span of Slab (Ly) + (1 X Developement Length) +(1 x inclined length) – (45° bend x 2)
Inclined Length = 0.42 D
= 4000 + (1 x 40 x 8) + (1 x 0.42 x D) – (1d x 2)
= 4000 + 320 + (0.42×88) – (1x8x2) = 4340.96mm or 4.34 m
Step 4
Find Top Bar (Extra) ; Top Bars are provided at the top of critical length (L/4) area, Please refer the drawing section AA
Number of Top bars on Ly side = (Lx/5) / spacing + 1 = (3000/5) / 150 +1 = 5 Nos
Length of top bar on Ly side = Clear Span of Slab (Ly) + (2 X Development Length)
= 4000+(2*40*12) = 4000+960 = 4960 mm or 4.96 m
Number of Top bars on Lx side = (Ly/5) / spacing + 1 = (4000/5) / 150 + 1 = 6 Nos
Length of top bar on Ly side = Clear Span of Slab (Ly) + (2 X Development Length)
= 3000+(2*40*12) = 3000+960 = 3960 mm or 3.96 m
Bar Bending Schedule for Two Way Slab
NOTE
 Here we have taken development length as 40d. However, In practice, the structural drawing itself has this dimension or else you have to extend the rod up to the beam end minus clear cover.